Editing Jump Drive (section)

===Jump Drive Efficiency===
Jump Drive Efficiency determines how large an engine needs to be in order to jump a particular size of ship. The higher the efficiency value, the more capacity you get per ton. 

In [[CSharp|C#]], jump drive sizes are as follows: 
 Drive size = Target ship size / Base Efficiency / Large Drive Efficiency Modifier 
and
 Military Large Drive Efficiency Modifier = (Drive size / 1000 tons) ^ 0.25
 Commercial Large Drive Efficiency Modifier = (Drive size / 5000 tons) ^ 0.25
The large drive modifier cannot be less than 1, so military drives under 1000 tons and commercial drives under 5000 tons are not affected by this modifier. 

In [[VB6]], for military jump drives, the max size of ship (in hull spaces; 1 HS = 50 tons) is given by <code>Efficiency * Size</code> For commercial drives, it's a little different. The efficiency of commercial engines is 0.75 x the Efficiency tech, but the size is multiplied by 10 compared to the size listed in the dialogue. The max ship size is thus <code>(0.75 * Efficiency Tech) * (10 * Size)</code>, and this is then rounded to the nearest 10 HS.

{| class="wikitable" style="text-align: center;"
! Efficiency !! 4 !! 5 !! 6 !! 8 !! 10 !! 12 !! 15 !! 18 !! 21 !! 25
|-
! RP cost ([[CSharp|C#]])
|1,000||2,000||4,000||8,000||15,000||30,000||60,000||120,000||250,000||500,000
|-
! RP cost ([[VB6]])
|2,000||4,000||8,000||15,000||30,000||60,000||120,000||250,000||500,000||1,000,000
|}